Mathematics Quesion Review (2025-11-05)
05/11/25 02:06
Question 1:
Given b≥x≥a , show that:
1/(x - a)^2 + 1/(b-x)^2 ≥ 8/(b-a)^2
05/11/25 02:07
Solution:
Consider AM ≥ GM
LHS will be the least when x=(a+b)/2
QED
05/11/25 02:10
Question 2:
Consider f'(x) = tan(x)/x for π/2≥x≥0,
show that f(x) ≥ π/4.
05/11/25 02:13
Solution:
tan(x) ≥ x ≥ sin(x) ≥ 0
So tan(x)/x ≥ 1
Integrating both side from 0 to π/4,
we obtain the desired result.