HKDSE Mathematics Question Review

Academic
#1 Turbattle
23/02/24 20:24

1. Prove the following arithmetic sum:

#2 Turbattle
23/02/24 20:26

2. Show that a recurring decimal is always a rational number.

#3 Turbattle
23/02/24 20:35

1. Prove the following arithmetic sum:

Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:

Area = xy/2 = (0 + n)n /2

QED

Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.

#4 Turbattle
23/02/24 20:44

2. Show that a recurring decimal is always a rational number.

Solution:

可見,如果數學卷唔考計算題只考論述題,

相信好多操卷仔會即時跪低,整體合格率大跌

#5 Turbattle
23/02/24 20:49

2. Show that a recurring decimal is always a rational number.

Solution:

可見,如果數學卷唔考計算題只考論述題,

相信好多操卷仔會即時跪低,整體合格率大跌

Erratum:

#6 Turbattle
23/02/24 20:54

2. Show that a recurring decimal is always a rational number.

Solution:

可見,如果數學卷唔考計算題只考論述題,

相信好多操卷仔會即時跪低,整體合格率大跌

Erratum:

Get stuck with the following value?

Multiply both the numerator and denominator by 10^k, and you are done.

#7 Turbattle
24/02/24 01:28

1. Prove the following arithmetic sum:

Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:

Area = xy/2 = (0 + n)n /2

QED

Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.

幅圖打錯,正確應為:

#8 Turbattle
24/02/24 01:30

1. Prove the following arithmetic sum:

Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:

Area = xy/2 = (0 + n)n /2

QED

Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.

幅圖打錯,正確應為:

#9 Turbattle
24/02/24 01:45

Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:

Area = xy/2 = (0 + n)n /2

QED

Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.

幅圖打錯,正確應為:

Now we visualize the sum:

Take n=5, we have the following blocks:

y

□ □ □ □ ■

□ □ □ ■ ■

□ □ ■ ■ ■

□ ■ ■ ■ ■ x

Then x-y =1

The sum is half of the rectangle,

I.e. sum = xy/2 = y (y+1) /2

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