HKDSE Mathematics Question Review
1. Prove the following arithmetic sum:
2. Show that a recurring decimal is always a rational number.
1. Prove the following arithmetic sum:
Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:
Area = xy/2 = (0 + n)n /2
QED
Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.
2. Show that a recurring decimal is always a rational number.
Solution:
可見,如果數學卷唔考計算題只考論述題,
相信好多操卷仔會即時跪低,整體合格率大跌
2. Show that a recurring decimal is always a rational number.
Solution:
可見,如果數學卷唔考計算題只考論述題,
相信好多操卷仔會即時跪低,整體合格率大跌
Erratum:
2. Show that a recurring decimal is always a rational number.
Solution:
可見,如果數學卷唔考計算題只考論述題,
相信好多操卷仔會即時跪低,整體合格率大跌
Erratum:
Get stuck with the following value?
Multiply both the numerator and denominator by 10^k, and you are done.
1. Prove the following arithmetic sum:
Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:
Area = xy/2 = (0 + n)n /2
QED
Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.
幅圖打錯,正確應為:
1. Prove the following arithmetic sum:
Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:
Area = xy/2 = (0 + n)n /2
QED
Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.
幅圖打錯,正確應為:
Solution: Put the sum into a Cartesian plane, we have 11 points (x_n, y_n), where x is number of piles and y is total increment. Now we have (0,0), (1,1), ... (n,n), then the sum is simply the area of a right angle triangle:
Area = xy/2 = (0 + n)n /2
QED
Likewise, if r=1, then Area = (n+1) n /2, which is exactly the sum of arithmetic progression.
幅圖打錯,正確應為:
Now we visualize the sum:
Take n=5, we have the following blocks:
y
□ □ □ □ ■
□ □ □ ■ ■
□ □ ■ ■ ■
□ ■ ■ ■ ■ x
Then x-y =1
The sum is half of the rectangle,
I.e. sum = xy/2 = y (y+1) /2